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calculation of individual heat flows 4.2.1 Radiant heat transfer Absolute temperatures: T_ogr = 12 273.15 = 285.15 K T_l = -4 273.15 = 269.15 K Radiant heat exchange: q_radiant = 5.67-10- 0.88 (285.15 269.15 ) 69.5 W/m 4.2.2 Convective heat exchange Heat transfer coefficient: = 3.14 3.55-w = 3.14 3.55-0.25 = 4.03 W/(m-K) Heat load: q_k = 4.03 (12 (-4)) = 4.03 16 = 64.5 W/m 4.2.3 Condensation load q_condens = 0.7 (/100) (t_v t_l) = 0.7 0.55 16 6.2 W/m 4.2.4 Heat conduction through the slab Lets use the enlarged value for the construction with insulation: q_pl = 8 W/m 4.2.5 Light absorption by ice Heat flux density: q_osv = (P_osv _pogl) / A = (22000 0.45) / 1800 5.5 W/m 4.2.6 Thermal effect of one pour (average per hour) Water mass: m = A h = 1000 1800 0.0006 = 1080 kg Thermal effect: Q_hall = m [ c_v-(t_vz 0) r c_l-|t_l| ] Substitution: c_v = 4200 J/(kg-K) c_l = 2100 J/(kg-K) r = 334000 J/kg t = 50 K Q_hall = 1080 [4200-50 334000 2100-4] = 5.96-10 J Conversion to kWh considering the interval between pours of 4 hours: Q_zal = 5.96-10 / (4 3.6-10 ) 42 kW Per m: q_exp = 42-1000 / 1800 23.3 W/m 4.3

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